Question
给你一个整数数组 nums,请你将该数组升序排列。
示例 1:
输入:nums = [5,2,3,1] 输出:[1,2,3,5]
示例 2:
输入:nums = [5,1,1,2,0,0] 输出:[0,0,1,1,2,5]
提示:
1 <= nums.length <= 5 * 104 -5 * 104 <= nums[i] <= 5 * 104
Related Topics 数组 分治 桶排序 计数排序 基数排序 排序 堆(优先队列) 归并排序 👍 535 👎 0
Answer
void quickSort(vector<int>&nums, int left, int right) {
if (left >= right) return;
int privot = nums[left];//privot选择左边的数,让j指针先向左移动
int i = left;
int j = right;
while(i < j) {
while(nums[j] >= privot && i < j) {
j--;
}
while(nums[i] <= privot && i < j) {
i++;
}
if (i<j) {
swap(nums[i], nums[j]);
}
}
for(auto it : nums) {
cout << it << " ";
}
cout << endl;
swap(nums[left], nums[i]);//i==j时
quickSort(nums, left, i-1);
quickSort(nums, i+1, right);
}
vector<int> sortArray(vector<int>& nums) {
quickSort(nums, 0, nums.size()-1);
return nums;
}
//快速排序,从大到小
//AC
void quickSort2(vector<int>&nums, int left, int right) {
if (left >= right) return;
int privot = nums[left];
int i = left;
int j = right;
while(i < j) {
while(nums[j] <= privot && i < j) {
j--;
}
while(nums[i] >= privot && i < j) {
i++;
}
if (i<j) {
swap(nums[i], nums[j]);
}
}
swap(nums[left], nums[i]);
quickSort2(nums, left, i-1);
quickSort2(nums, i+1, right);
}
Attention
- privot选择左边的数,让j指针先向左移动,privot选择右边的数,让指针i先向右移动。i==j时交换。