Question
实现二叉树的前中后序遍历
Answer
struct TreeNode {
int val;
TreeNode *left;
TreeNode *right;
TreeNode() : val(0), left(nullptr), right(nullptr) {}
TreeNode(int x) : val(x), left(nullptr), right(nullptr) {}
TreeNode(int x, TreeNode *left, TreeNode *right) : val(x), left(left), right(right) {}
};
void inOrder(TreeNode *root, vector<int> &res) {
if (!root) return;
if (root->left) {
inOrder(root->left, res);
}
res.push_back(root->val);
if (root->right) {
inOrder(root->right, res);
}
}
void postOrder(TreeNode *root, vector<int> &res) {
if (!root) return;
if (root->left) {
postOrder(root->left, res);
}
if (root->right) {
postOrder(root->right, res);
}
res.push_back(root->val);
}
void preOrder(TreeNode *root, vector<int> &res) {
if (!root) return;
res.push_back(root->val);
if (root->left) {
preOrder(root->left, res);
}
if (root->right) {
preOrder(root->right, res);
}
}
//94
vector<int> inorderTraversal(TreeNode* root) {
vector<int> res;
inOrder(root, res);
return res;
}
//144
vector<int> preorderTraversal(TreeNode* root) {
vector<int> res;
preOrder(root, res);
return res;
}
//145
vector<int> postorderTraversal(TreeNode* root) {
vector<int> res;
postOrder(root, res);
return res;
}
// 3
// / \
// 9 20
// / \
// 15 7
//inout : [3,9,20,null,null,15,7]
//vector<int> level_vecs = {3,9,20,-1,-1,15,7};
//levelOrderByQueue
//102
vector<vector<int>> levelOrder(TreeNode* root) {
//迭代
//广度优先搜索(BFS队列)
vector<vector<int>> res;
if (!root)
return res;
queue<TreeNode*> q;
q.push(root);
while(!q.empty()) {
res.emplace_back();//容器尾部添加一个元素
int len = q.size();
for (int i = 0; i < len; i++) {
TreeNode* node = q.front();
res.back().push_back(node->val);
q.pop();
if (node->left) {
q.push(node->left);
}
if (node->right) {
q.push(node->right);
}
}
}
return res;
}
void leveOrderByQueue(TreeNode* root) {
queue<TreeNode*> q;
if (root != nullptr) {
q.push(root);
}
while (!q.empty()) {
TreeNode *node = q.front();
cout << "node: " << node->val << endl;
if (node->left) {
q.push(node->left);
}
if (node->right) {
q.push(node->right);
}
q.pop();
}
}
//107
//自底向上的层序遍历
vector<vector<int>> levelOrderBottom(TreeNode* root) {
vector<vector<int>> res;
if (!root)
return res;
queue<TreeNode*> q;
q.push(root);
while(!q.empty()) {
res.emplace_back();
int len = q.size();
for (int i = 0; i < len; i++) {
TreeNode* node = q.front();
res.back().push_back(node->val);
q.pop();
if (node->left) {
q.push(node->left);
}
if (node->right) {
q.push(node->right);
}
}
}
reverse(res.begin(), res.end());
return res;
}